[Carpet] Prolongation order
Erik Schnetter
schnetter at cct.lsu.edu
Thu Apr 3 18:40:58 CEST 2008
On Apr 3, 2008, at 10:57:30, Ian Hinder wrote:
> Erik Schnetter wrote:
>> On Apr 3, 2008, at 10:28:02, Ian Hinder wrote:
>>> But from your description above, I would have thought the number of
>>> ghost zones required would be 2 for the 5th order stencil, but
>>> (prolongation_order_space+1)/2 gives 3?
>>
>> A 5th order stencil (where "5" is counted according to Carpet
>> conventions) requires 6 points, hence 3 the stencil radius is 3.
>
> o o o o o o o o o o o o o o o o o
> |
> X (X) (X) (X) (X) (X) (X) X X
>
> So in principle, Carpet picks one of the adjacent coarse points to the
> fine point it wants to interpolate, and identifies which processor
> it is
> on. That processor is then asked to interpolate, which requires it to
> have all six points, meaning that at least in one of the directions,
> three additional points are required. OK - getting clearer!
Yes, exactly.
-erik
--
Erik Schnetter <schnetter at cct.lsu.edu> http://www.cct.lsu.edu/~eschnett/
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